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clc
clear
printf("example 3.27 page number 114\n\n")
//to find the area of heating surface
F = 1000 //in kg
xF = 0.01
solid_feed = F*xF;
water_feed = F - solid_feed;
tF = 40 //in degree C
hF = 167.5 //in kJ/kg
xL = 0.02;
solid_liquor = 10 //in kg
L = solid_liquor/xL;
tL = 100 //in degree C
hL = 418.6 //in kJ/kg
V = F -L;
tv = 100 //in degree C
Hv = 2675 //in kJ/kg
ts = 108.4 //in degree C
Hs = 2690 //in kJ/kg
tc = 108.4 //in degree C
hc = 454 //in kJ/kg
//applying heat balance
S = (F*hF-V*Hv-L*hL)/(hc-Hs);
printf("weight of steam required = %f kg/hr",S)
Q = S*(Hs-hc);
U = 1.4 //in kW/m2K
delta_t = ts-tL;
A = 383.2/(U*delta_t);
printf("\n\narea of heating surface = %f square meter",A)
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