blob: be4e8f6a3d9e6132ef1ded461310d496f85c4a91 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
|
The force produces deflection in both the portions of steel.
Total deflection will be sum of inividual deflections.
The deflection is given by:
x=(F*L)/(A*E)
x=x1+x2
The total deflection is 3.183 mm
Stress=Force/Area
The tensile stress at larger cross section area is 25.46 MPa
The tensile stress at smaller cross section area is 101.86 MPa
|