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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+The force produces deflection in both the portions of steel.
+Total deflection will be sum of inividual deflections.
+The deflection is given by:
+ x=(F*L)/(A*E)
+ x=x1+x2
+
+The total deflection is 3.183 mm
+
+ Stress=Force/Area
+
+The tensile stress at larger cross section area is 25.46 MPa
+The tensile stress at smaller cross section area is 101.86 MPa \ No newline at end of file