blob: af945197c296c39dee64860a186f64f53587ad56 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
|
Let the diameter of shaft be d
Bending Stress Sx= M*c/I
where c=d/2
I=(pi/64)*d^4
Shear stress Txy=T*r/J
where r=d/2
J=(pi/32)*d^4
Maximum shear stress
Tmax=sqrt( ((Sx-Sy)/2)^2 + (Txy^2) )
where Tmax is 75MN/m^2 and Sy=0
diameter
d=( (16* sqrt( M^2 + T^2 )) / (Ss*pi) )^1/3
The calculated diameter is 0.0357 m
Standardizing the above value, we get
d=0.0360 m = 36.0 mm
|
