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+Let the diameter of shaft be d
+
+Bending Stress Sx= M*c/I
+ where c=d/2
+ I=(pi/64)*d^4
+
+Shear stress Txy=T*r/J
+ where r=d/2
+ J=(pi/32)*d^4
+
+Maximum shear stress
+ Tmax=sqrt( ((Sx-Sy)/2)^2 + (Txy^2) )
+where Tmax is 75MN/m^2 and Sy=0
+diameter
+ d=( (16* sqrt( M^2 + T^2 )) / (Ss*pi) )^1/3
+
+The calculated diameter is 0.0357 m
+Standardizing the above value, we get
+
+ d=0.0360 m = 36.0 mm \ No newline at end of file