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//Value of P
//Refer fig.5.8
//consider equilibrium
mu=0.2
//750N block
N1=750*cosd(60) //N
F1=mu*N1 //N
T=F1+750*sind(60) //N
//500N block
//N2=500-0.5P
//Law of friction
//F2=0.2*N2
P=(724.52+100)/(cosd(30)+0.1) //N
printf("\nP=%0.2f N",P)
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