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+//Value of P
+//Refer fig.5.8
+//consider equilibrium
+mu=0.2
+//750N block
+N1=750*cosd(60) //N
+F1=mu*N1 //N
+T=F1+750*sind(60) //N
+//500N block
+//N2=500-0.5P
+//Law of friction
+//F2=0.2*N2
+P=(724.52+100)/(cosd(30)+0.1) //N
+printf("\nP=%0.2f N",P)
+