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//Least value of alpha and reactions developed
//refer fig. 5.16
//Using law of friction and equilibrium
//FA=0.25*NA
//FB=0.4*NB
//NA+0.4*NB=1100
//0.25*NA=NB
//Solving this we get
NA=1000 //N
FA=0.25*NA //N
NB=0.25*NA //N
FB=0.4*250 //N
//Taking moment about A
alpha=atand(3) //degree
printf("\nNA=%0.2f N\nFA=%0.2f N\nNB=%0.2f N\nFB=%0.2f N\nalpha=%0.2f degree",NA,FA,NB,FB,alpha)
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