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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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+//Least value of alpha and reactions developed
+//refer fig. 5.16
+//Using law of friction and equilibrium
+//FA=0.25*NA
+//FB=0.4*NB
+//NA+0.4*NB=1100
+//0.25*NA=NB
+//Solving this we get
+NA=1000 //N
+FA=0.25*NA //N
+NB=0.25*NA //N
+FB=0.4*250 //N
+//Taking moment about A
+alpha=atand(3) //degree
+printf("\nNA=%0.2f N\nFA=%0.2f N\nNB=%0.2f N\nFB=%0.2f N\nalpha=%0.2f degree",NA,FA,NB,FB,alpha)