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//Ball dropped from height
//refer fig. 18.11
g=9.81 //m/sec^2
h0=1.2 //m
uy=sqrt(2*g*h0) //downward
h1=1 //m
v1y=sqrt(2*9.81*h1) //upwards
e=sqrt(1/1.2)
//Time of flight
t1=(2*sqrt(2*9.81*1))/(9.81) //sec
ux=0.4/0.903 //m/sec
//Vertical component of velocity after second bounce
v2y=0.903*sqrt(2*9.81*1) //m/sec
h2=((v2y)^2)/(2*9.81) //m
t2=(2*4)/(9.81) //sec
//Horizontal range
D2=0.443*0.815 //m
printf("\ne=%.3f \nh2=%.3f m \nD2=%.3f m ",e,h2,D2)
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