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authorprashantsinalkar2018-02-03 11:01:52 +0530
committerprashantsinalkar2018-02-03 11:01:52 +0530
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+//Ball dropped from height
+//refer fig. 18.11
+g=9.81 //m/sec^2
+h0=1.2 //m
+uy=sqrt(2*g*h0) //downward
+h1=1 //m
+v1y=sqrt(2*9.81*h1) //upwards
+e=sqrt(1/1.2)
+//Time of flight
+t1=(2*sqrt(2*9.81*1))/(9.81) //sec
+ux=0.4/0.903 //m/sec
+//Vertical component of velocity after second bounce
+v2y=0.903*sqrt(2*9.81*1) //m/sec
+h2=((v2y)^2)/(2*9.81) //m
+t2=(2*4)/(9.81) //sec
+//Horizontal range
+D2=0.443*0.815 //m
+printf("\ne=%.3f \nh2=%.3f m \nD2=%.3f m ",e,h2,D2)