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//Chapter 8 Chemical Equlibrium
clc;
clear;
//Initialisation of Variables
k= 1.1*10**-5
V= 600 //ml
n= 0.4 //mole
//CALCULATIONS
m= n*1000/V
x= (-k+sqrt(k**2+4*4*0.67*k))/(2*4)
M= 2*x
P= x*100/m
//RESULTS
mprintf("Molar concentration of NO2= %.2e mol per litre",M)
mprintf("\nPer cent dissociation= %.2f percent",P)
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