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+//Chapter 8 Chemical Equlibrium
+
+clc;
+clear;
+
+//Initialisation of Variables
+k= 1.1*10**-5
+V= 600 //ml
+n= 0.4 //mole
+
+//CALCULATIONS
+m= n*1000/V
+x= (-k+sqrt(k**2+4*4*0.67*k))/(2*4)
+M= 2*x
+P= x*100/m
+
+//RESULTS
+mprintf("Molar concentration of NO2= %.2e mol per litre",M)
+mprintf("\nPer cent dissociation= %.2f percent",P)