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//===========================================================================
//chapter 11 example 3
clc;
clear all;
//variable declaration
R = 400; //total resistance of slide-wire of 200 cmin Ω
L1 = 101.8; //length of slide wire in cm
L = 200; //length of wire in cm
v1 = 1.018; //voltage drop across 101.8cm length of slide wire in V
v = 3; //battery voltage in V
a = 0.2; //it is possible to read a of 1 mm
//calculations
R1 = (R/L)*L1; //resistance of slide wire of 101.8 cm in Ω
I1 = v1/R1; //working current in A
RT = v/I1; //total resistance of battery circuit in Ω
RR = RT-R; //resistance of series rheostat in Ω
r = I1*R; //measuring range in V
//since 200cm length represents 2 V
//1 mm length represents = z
z = (r/L)*(1/10); //voltage represented for 1mm length
Ri = z*a; //resolution of instrument in mV
//result
mprintf("working current = %3.1e A",(I1*10^3));
mprintf("\nresistance of series rheostat = %3.2f Ω",RR);
mprintf("\nmeasuring range = %3.2f V",r);
mprintf("\nresolution of the instrument = %3.2f mV",(Ri*10^3));
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