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clear
//
//
//Initilization of Variables
P_e=300 //N/mm**2 //Elastic Limit in tension
FOS=3 //Factor of safety
mu=0.3 //Poissons ratio
P=12*10**3 //N Pull
Q=6*10**3 //N //Shear force
//Calculations
//Let d be the diameter of the shaft
//Direct stress
//P_x=P*(%pi*4**-1*d**3)**-1
//After substituting values and further simplifying we get
//P_x=48*10**3
//Now shear stress at the centre of bolt
//q=4*3**-1*q_av
//After substituting values and further simplifying we get
//q=32*10**3*(%pi*d**2)**-1
//Principal stresses are
//P1=P_x*2**-1+((P_x*2**-1)**2+q**2)**0.5
//After substituting values and further simplifying we get
//p1=20371.833*(d**2)**-1
//P2=P_x*2**-1-((P_x*2**-1)**2+q**2)**0.5
//After substituting values and further simplifying we get
//P2=-5092.984*(d**2)**-1
//q_max=((P_x*2**-1)**2+q**2)**0.5
//From Max Principal stress theory
//Permissible stress in Tension
P1=100 //N/mm**2
d=(20371.833*P1**-1)**0.5
//Max strain theory
//e_max=P1*E**-1-mu*P2*E**-1
//After substituting values and further simplifying we get
//e_max=21899.728*(d**2*E)**-1
//According to this theory,the design condition is
//e_max=P_e*(E*FOS)**-1
//After substituting values and further simplifying we get
d2=(21899.728*3*300**-1)**0.5 //mm
//Max shear stress theory
//e_max=shear stress at elastic*(FOS)**-1
//After substituting values and further simplifying we get
d3=(12732.421*6*300**-1)**0.5 //mm
//Result
printf("\n Diameter of Bolt by:Max Principal stress theory %0.2f mm",d)
printf("\n :Max strain theory %0.2f mm",d2)
printf("\n :Max shear stress theory %0.2f mm",d3)
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