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//Chapter 16, Example 16.2
clc
//Initialisation
E=5 //voltage
R=1000 //resistance in ohm
Vd=0.7 //barrier voltage
ron=10 //internal resistance in ohm
//Calculation
I=E/R //current in ampere
I1=(E-Vd)/R //current in ampere
I2=(E-Vd)/(R+ron) //current in ampere
//Results
printf("When no voltage drop, I = %d mA\n",I*1000)
printf("When there is conduction voltage of the diode, I = %.1f mA\n",I1*1000)
printf("When there is conduction voltage and internal resistance if the diode, I2 = %.2f mA\n",I2*1000)
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