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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3809/CH16/EX16.2/EX16_2.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '3809/CH16/EX16.2/EX16_2.sce')
-rw-r--r-- | 3809/CH16/EX16.2/EX16_2.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/3809/CH16/EX16.2/EX16_2.sce b/3809/CH16/EX16.2/EX16_2.sce new file mode 100644 index 000000000..037742c3b --- /dev/null +++ b/3809/CH16/EX16.2/EX16_2.sce @@ -0,0 +1,17 @@ +//Chapter 16, Example 16.2
+clc
+//Initialisation
+E=5 //voltage
+R=1000 //resistance in ohm
+Vd=0.7 //barrier voltage
+ron=10 //internal resistance in ohm
+
+//Calculation
+I=E/R //current in ampere
+I1=(E-Vd)/R //current in ampere
+I2=(E-Vd)/(R+ron) //current in ampere
+
+//Results
+printf("When no voltage drop, I = %d mA\n",I*1000)
+printf("When there is conduction voltage of the diode, I = %.1f mA\n",I1*1000)
+printf("When there is conduction voltage and internal resistance if the diode, I2 = %.2f mA\n",I2*1000)
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