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//Book Name:Fundamentals of Electrical Engineering
//Author:Rajendra Prasad
//Publisher: PHI Learning Private Limited
//Edition:Third ,2014
//Ex4_29.sce.
clc;
clear;
Q1=60e-6; //Capacitor charges in coulomb
V1=180; //Volatge in volt
C1=Q1/V1;
C2=4*C1;
Q2=0;
E1=(1/2)*C1*V1^2; //Before two capacitance are joined the energy stored in C1
E2=0; //Energy stored in C2
Ea=E1+E2; //Total energy before two capacitors are joined
V=(Q1+Q2)/(C1+C2); //Potential in volt
E1=(1/2)*C1*V^2; //Energy stored in C1 in joule
E2=(1/2)*C2*V^2; //Energy stored in C2 in joule
Eb=E1+E2; //Total energy after two capacitors are joined
E_loss=Ea-Eb;
printf("\n Loss of energy=%2.1f*10^-4 joule",E_loss*1e4)
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