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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex4_29.sce.
+
+clc;
+clear;
+Q1=60e-6;   //Capacitor charges in coulomb
+V1=180;     //Volatge in volt
+
+C1=Q1/V1;
+C2=4*C1;
+Q2=0;
+E1=(1/2)*C1*V1^2;                //Before two capacitance are joined the energy stored in C1
+E2=0;                        //Energy stored in C2
+Ea=E1+E2;                   //Total energy before two capacitors are joined
+V=(Q1+Q2)/(C1+C2);          //Potential in volt
+
+E1=(1/2)*C1*V^2;       //Energy stored in C1 in joule
+E2=(1/2)*C2*V^2;       //Energy stored in C2 in joule
+Eb=E1+E2;                //Total energy after two capacitors are joined
+
+E_loss=Ea-Eb;
+printf("\n Loss of energy=%2.1f*10^-4 joule",E_loss*1e4)
+