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clear
//Given
u=-15.0 //cm
f=-10 //cm
o=2.0 //cm
//Calculation
v=1/((1.0/f)-(1.0/u))
m=v/u
I=-m*o
//Result
printf("\n Position of the image is %0.3f cm", v)
printf("\n Size of the image is %0.3f cm",I)
printf("\n Nature of the image isreal and inverted ")
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