clear
//Given
u=-15.0                             //cm
f=-10                             //cm
o=2.0                              //cm

//Calculation
v=1/((1.0/f)-(1.0/u))
m=v/u
I=-m*o

//Result
printf("\n Position of the image is %0.3f  cm", v)
printf("\n Size of the image is %0.3f  cm",I)
printf("\n Nature of the image isreal and inverted ")