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clc
//
//Variable declaration
cosB=12/13.0
//Calculation
//Centroid
Y=((2*65*3*30)/((2*65*3)+((50)*(3)))) // Distance y(mm)
//Centroidal Moment of Inertia
b=(3)/(cosB) // Distance(mm)
I=2*((1/12.0)*(3.25)*((60**3)) + (3.25)*(60)*((8.33**2))) + ((1/12.0)*(50)*((3**3)) + (50)*(3)*((21.67**2)))// Moment of inertia(mm**4)
I=(I/((10**12))) // Moment of inertia(m**4)
//Shearing Stress at A
ta=0
//Maximum Shearing Stress
Q=(3.25*38.33*(38.33/2.0))
tE=((5)*(2.387*((10**-6))))/((0.2146*((10**-6)))*(0.003))
tE=(tE/1000.0) // Largest shearing stress
// Result
printf("\n Case(a) Shearing stress at A = %0.3f ksi' ,ta)
printf("\n Case(a) Maximum shearing stress = %0.3f MPa' ,tE)
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