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+clc
+//
+
+//Variable declaration
+cosB=12/13.0
+
+//Calculation
+//Centroid
+Y=((2*65*3*30)/((2*65*3)+((50)*(3)))) // Distance y(mm)
+
+//Centroidal Moment of Inertia
+b=(3)/(cosB) // Distance(mm)
+I=2*((1/12.0)*(3.25)*((60**3)) + (3.25)*(60)*((8.33**2))) + ((1/12.0)*(50)*((3**3)) + (50)*(3)*((21.67**2)))// Moment of inertia(mm**4)
+I=(I/((10**12))) // Moment of inertia(m**4)
+//Shearing Stress at A
+ta=0
+//Maximum Shearing Stress
+Q=(3.25*38.33*(38.33/2.0))
+
+tE=((5)*(2.387*((10**-6))))/((0.2146*((10**-6)))*(0.003))
+tE=(tE/1000.0) // Largest shearing stress
+
+
+// Result
+printf("\n Case(a) Shearing stress at A = %0.3f ksi' ,ta)
+printf("\n Case(a) Maximum shearing stress = %0.3f MPa' ,tE)