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clear//
//Variables
V = 6.0 //Applied voltage (in volts)
R0 = 0.2 //Resistance (in ohm)
R1 = 2.0 //Resistance (in ohm)
R2 = 3.0 //Resistance (in ohm)
R3 = 6.0 //Resistance (in ohm)
//Calculation
Req = 1 / (1/R1 + 1/R2 + 1/R3) //Equivalent Resistance (in ohm)
R = R0 + Req //Total Resistance (in ohm)
I = V/R //Current (in Ampere)
V0 = I * R0 //Voltage drop across R0 (in volts)
Veq = V - V0 //Voltage drop across Req (in volts)
I1 = Veq / R1 //Current through R1 (in Ampere)
I2 = Veq / R2 //Current through R2 (in Ampere)
I3 = Veq / R3 //Current through R3 (in Ampere)
P = V * I //Power supplied by the voltage source (in volts)
I0 = V/R0 //Current in case of 'Short' across DE (in Ampere)
P0 = V * I0 //Power dissipated in case of 'Short' (in watt)
//Result
printf("\n Total Resistance is %0.3f ohm.",R)
printf("\n Branch Currents :\nThrough R1 = %0.3f A.\nThrough R2 = %0.3f A.\nThrough R3 = %0.3f A.",I1,I2,I3)
printf("\n Current supplied by voltage source is %0.3f A.",I)
printf("\n Power supplied by the voltage source is %0.3f W.",P)
printf("\n Current supplied in case of Short across DE is %0.3f A.",I0)
printf("\n Power supplied in case of Short acorss DE is %0.3f A.",P0)
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