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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
treedbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3754/CH4/EX4.15/4_15.sce
parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+clear//
+
+//Variables
+
+V = 6.0 //Applied voltage (in volts)
+R0 = 0.2 //Resistance (in ohm)
+R1 = 2.0 //Resistance (in ohm)
+R2 = 3.0 //Resistance (in ohm)
+R3 = 6.0 //Resistance (in ohm)
+
+//Calculation
+
+Req = 1 / (1/R1 + 1/R2 + 1/R3) //Equivalent Resistance (in ohm)
+R = R0 + Req //Total Resistance (in ohm)
+I = V/R //Current (in Ampere)
+V0 = I * R0 //Voltage drop across R0 (in volts)
+Veq = V - V0 //Voltage drop across Req (in volts)
+I1 = Veq / R1 //Current through R1 (in Ampere)
+I2 = Veq / R2 //Current through R2 (in Ampere)
+I3 = Veq / R3 //Current through R3 (in Ampere)
+P = V * I //Power supplied by the voltage source (in volts)
+I0 = V/R0 //Current in case of 'Short' across DE (in Ampere)
+P0 = V * I0 //Power dissipated in case of 'Short' (in watt)
+
+//Result
+
+printf("\n Total Resistance is %0.3f ohm.",R)
+printf("\n Branch Currents :\nThrough R1 = %0.3f A.\nThrough R2 = %0.3f A.\nThrough R3 = %0.3f A.",I1,I2,I3)
+printf("\n Current supplied by voltage source is %0.3f A.",I)
+printf("\n Power supplied by the voltage source is %0.3f W.",P)
+printf("\n Current supplied in case of Short across DE is %0.3f A.",I0)
+printf("\n Power supplied in case of Short acorss DE is %0.3f A.",P0)