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//Fluid Systems- By Shiv Kumar
//Chapter 7- Performance of Water Turbine
//Example 7.11
// To Find (a)Power Developed by Model (b)Ratio of Heads and Ratio of Mass Flow Rates between Prototype and Model.
clc
clear
//Given:-
Pp=12; //Power Developed by Prototype,MW
Lr=1/10; //Scale Ratio
DmbyDp=Lr;
LmbyLp=Lr;
//Computations:-
//(a)Power Developed by the Model
//As Np=Nm and effeciencies of prototype and model are equal
Pm=Pp*10^6*(DmbyDp)^5; //W
//(b)Ratio of Heads and Ratio of Mass flow Rates
HpbyHm=DmbyDp^(-2); //Dimensionless
QpbyQm=DmbyDp^(-3)
//As m=rho*Q and rho is Constant. So,
m_pbym_m=QpbyQm;
//Results
printf("(a)Power Developed by the Model,Pm=%.f W\n",Pm)
printf(" (b)Ratio of Heads, Hp/Hm=%.f\n Ratio of Mass flow rates, m_p/m_m=%.f\n",HpbyHm,m_pbym_m)
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