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+//Fluid Systems- By Shiv Kumar
+//Chapter 7- Performance of Water Turbine
+//Example 7.11
+// To Find  (a)Power Developed by Model   (b)Ratio of Heads and Ratio of Mass Flow Rates between Prototype and Model.
+   clc
+   clear
+
+//Given:-
+      Pp=12;       //Power Developed by Prototype,MW
+      Lr=1/10;        //Scale Ratio
+      DmbyDp=Lr;
+       LmbyLp=Lr;
+
+
+//Computations:-
+
+     //(a)Power Developed by the Model
+                   //As Np=Nm and effeciencies of prototype and model are equal
+          Pm=Pp*10^6*(DmbyDp)^5;      //W
+          
+     //(b)Ratio of Heads and Ratio of Mass flow Rates
+         HpbyHm=DmbyDp^(-2);            //Dimensionless
+         QpbyQm=DmbyDp^(-3)
+        //As m=rho*Q   and  rho is Constant. So,
+         m_pbym_m=QpbyQm;
+
+//Results
+
+    printf("(a)Power Developed by the Model,Pm=%.f W\n",Pm)
+    printf(" (b)Ratio of Heads, Hp/Hm=%.f\n    Ratio of Mass flow rates, m_p/m_m=%.f\n",HpbyHm,m_pbym_m)
+
+
+