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//Fluid System By Shiv Kumar
//Chapter 6 - Kaplan and Propeller Turbines
//Example 6.2
//To Find Diameter of Runner, Speed of Runner and Specific Speed of Turbine
clc
clear
//Given:
P=8; //Shaft Power, MW
H=6; //Head, m
Ku=2.09; //Speed Ratio
Kf=0.68; //Flow Ratio
eta_0=90/100; //Overall Efficiency
dbyD=1/3; //Ratio of Diameters of Hub and Runner
//Data Required:
rho=1000; //Density of Water, Kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations
Q=P*10^6/(rho*g*H*eta_0); //Discharge, m^3/s
d=sqrt(Q/((%pi/4)*Kf*sqrt(2*g*H)*(dbyD^-2-1))); //Diameter of hub, m
D=d/dbyD; //Diameter of runner, m
N=Ku*60*sqrt(2*g*H)/(%pi*D); //Speed of Runner, rpm
Ns=N*(P*10^3)^(1/2)/(H^(5/4)); //Specific Speed of Turbine, SI Units
//Results
printf("Diameter of Runner, D =%.1f m \n",D)
printf("Speed of Runner, N = %.2f rpm \n",N) //The answer provided in the textbook is wrong
printf("Specific Speed of Turbine, Ns = %.2f (SI Units)",Ns) //The answer provided in the textbook is wrong(Due to error in N)
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