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+//Fluid System By Shiv Kumar
+//Chapter 6 - Kaplan and Propeller Turbines
+//Example 6.2
+//To Find Diameter of Runner, Speed of Runner and Specific Speed of Turbine
+
+     clc
+     clear
+
+//Given:
+   P=8;   //Shaft Power, MW
+   H=6;   //Head, m
+   Ku=2.09;       //Speed Ratio
+   Kf=0.68;     //Flow Ratio
+   eta_0=90/100;  //Overall Efficiency
+   dbyD=1/3;   //Ratio of Diameters of Hub and Runner
+   
+//Data Required:
+   rho=1000;   //Density of Water, Kg/m^3
+   g=9.81;     //Acceleration due to gravity, m/s^2
+
+//Computations
+
+     Q=P*10^6/(rho*g*H*eta_0);  //Discharge, m^3/s
+     d=sqrt(Q/((%pi/4)*Kf*sqrt(2*g*H)*(dbyD^-2-1)));   //Diameter of hub, m
+     D=d/dbyD;  //Diameter of runner, m
+     N=Ku*60*sqrt(2*g*H)/(%pi*D);  //Speed of Runner, rpm
+     Ns=N*(P*10^3)^(1/2)/(H^(5/4));   //Specific Speed of Turbine, SI Units
+ 
+//Results
+  printf("Diameter of Runner, D =%.1f m \n",D)
+  printf("Speed of Runner, N = %.2f rpm \n",N)   //The answer provided in the textbook is wrong
+  printf("Specific Speed of Turbine, Ns = %.2f (SI Units)",Ns)  //The answer provided in the textbook is wrong(Due to error in N)