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//Fluid Systems - By - Shiv Kumar
//Chapter 4 - Pelton Turbine (Impulse Turbine)
//Example 4.18
clc
clear
//Given Data:-
Ns=15; //Specific Speed
P=1200; //Shaft Power, kW
Ht=500; //Total Head at reservoir, m
Loss_per=5; //Percentage of Head loss in Pipe friction
Cv=0.98; //Co-efficient of Velocity
Ku=0.45; //Speed Ratio
eta_o=85/100; //Overall Efficiency
n=2; //Number of Jets
//Data Used:-
rho=1000; //Density of water, kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
H=Ht-Loss_per/100*Ht; //Effective Head, m
//(a)Speed of Runner, N
N=Ns*H^(5/4)/sqrt(P/n); //rpm
//(b)Diameter od each Jet, d
Q=P*1000/(rho*g*H*eta_o); //Net Discharge, m^3/s
q=Q/n; //Net Discharge per Jet, m^3/s
Vi=Cv*sqrt(2*g*H); //m/s
d=sqrt(q/((%pi/4)*Vi)); //m
//(c)Mean Diameter of Bucket Circle, D
D=Ku*60*sqrt(2*g*H)/(%pi*N); //m
//(d)Number of Buckets in the Runner, Z
Z=round(0.5*D/d+15);
//Results:-
printf(" (a)Speed of the Runner, N=%.f rpm\n",N)
printf(" (b)Diameter od each Jet, d =%.3f m\n",d)
printf(" (c)Mean Diameter of Bucket Circle, D =%.3f m\n",D)
printf(" (d)Number of Buckets on the Runner, Z =%.f \n",Z)
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