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//Fluid Systems - By - Shiv Kumar
//Chapter 4 - Pelton Turbine (Impulse Turbine)
//Example 4.15
clc
clear
//Given Data:-
H=120; //Head, m
d=74; //Diameter of Jet, mm
Q=200; //Discharge, litres/s
P=202.766; //Shaft Power, kW
P_mr=3.2; //Power lost in mechanical resistance, kW
//Data Used:-
rho=1000; //Density of water, kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
Q=Q/1000; //m^3/s
d=d/1000; //m
P=P*1000; //W
P_mr=P_mr*1000; //W
Vi=Q/((%pi/4)*d^2); //m/s
P_n=(rho*Q*g*H-rho*Q*Vi^2/2)/1000; //Power lost in Nozzle, kW
P_hr=(rho*Q*g*H-(P+P_n*1000+P_mr))/1000; //Power lost due to hydraulic resistance in Runner, kW
//Results:-
printf("(a) Power lost in Nozzle=%.3f kW\n",P_n) //The answer vary due to round off error
printf(" (b)Power lost due to Hydraulic Resistance in Runner =%.2f kW\n",P_hr) //The answer vary due to round off error
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