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+//Fluid Systems - By - Shiv Kumar
+//Chapter 4 - Pelton Turbine (Impulse Turbine)
+//Example 4.15
+  
+      clc
+       clear
+
+//Given Data:-
+      H=120;     //Head, m
+      d=74;        //Diameter of Jet, mm
+      Q=200;       //Discharge,  litres/s
+      P=202.766;        //Shaft Power, kW
+      P_mr=3.2;       //Power lost in mechanical resistance,  kW 
+
+
+//Data Used:-
+        rho=1000;          //Density of water, kg/m^3
+         g=9.81;            //Acceleration due to gravity, m/s^2
+
+//Computations:-
+              Q=Q/1000;          //m^3/s
+              d=d/1000;        //m
+             P=P*1000;      //W
+             P_mr=P_mr*1000;      //W
+
+            Vi=Q/((%pi/4)*d^2);        //m/s
+            P_n=(rho*Q*g*H-rho*Q*Vi^2/2)/1000;        //Power lost in Nozzle, kW
+            P_hr=(rho*Q*g*H-(P+P_n*1000+P_mr))/1000;    //Power lost due to hydraulic resistance in Runner, kW
+
+
+//Results:-
+     printf("(a) Power lost in Nozzle=%.3f kW\n",P_n)       //The answer vary due to round off error
+     printf(" (b)Power lost due to Hydraulic Resistance in Runner =%.2f kW\n",P_hr)       //The answer vary due to round off error   
+
+