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//Fluid system - By - Shiv Kumar
//Chapter 4 - Pelton Turbine (Impulse Turbine)
//Example 4.10
clc
clear
//Given Data:-
N=300; //Speed of runner, rpm
H=510; //Head, m
d=200; //Diameter of the Jet, mm
AoD=165; //Angle of Deflection, degrees
Vel_per=15; //percentage by which velocity is reduced
//Data Used:-
rho=1000; //Density of water, kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
Cv=0.98;
Ku=0.46;
//Computations:-
d=d/1000; //m
beta_O=180-AoD; //degrees
Vro_by_Vri=1-Vel_per/100; //Vro/Vri
Vi=Cv*sqrt(2*g*H); //m/s
Vwi=Vi;
ui=Ku*sqrt(2*g*H); //m/s
uo=ui;
u=ui;
Vri=Vi-ui; //m/s
Vro=Vri*Vro_by_Vri; //m/s
Vrwo=Vro*cosd(beta_O); //m/s
Vwo=uo-Vrwo; //m/s
//(i) Water power available at inlet of turbine, P
Q=(%pi/4)*d^2*Vi; //m^3.s
P=(1/2)*rho*Q*Vi^2/1000; //kW
//(ii)Resultant force on the bucket, F
F=rho*Q*(Vwi-Vwo)/1000; //kN
//(iii)Overall Efficiency, eta_o
eta_H=F*u/P; //Hydraulic efficiency
//Assume,
eta_V=100/100; //Volumetric efficiency is 100%
eta_m=98/100 //Mechanical Efficiency is 98%
eta_O=eta_V*eta_H*eta_m*100; //In percentage
//Results:-
printf("(i)Water power available at inlet of turbine=%.2f kW \n", P) //The answer provided in the Textbook is wrong
printf("(ii)Resultant force on the bucket, F=%.3f kN \n", F) //The answer vary due to round off error
printf("(iii)Overall efficiency, eta_O=%.2f percent", eta_O) //The answer vary due to round off error
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