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//Fluid Systems - By - Shiv Kumar
//Chapter 11- Centrifugal Pumps
//Example 11.10
//To Find (i)Manometric Head (ii)Manometric Efficiency (iii)Overall Efficiency of the Pump.
clc
clear
//Given Data:-
Do=480; //External Diameter of the Impeller, mm
Di=240; //Internal Diameter of the Impeller, mm
N=1000; //Speed, rpm
Q=0.0576; //Rate of Flow, m^3/s
Vfo=2.4; //Velocity of Flow, m/s
Vfi=Vfo;
Ds=180; //Diameter of Suction Pipe, mm
Dd=120; //Diameter of Delivery Pipe, mm
h_s=6.2; //Suction Head, m of water (abs)
h_d=30.2; //Delivery Head, m of water (abs)
P=35; //Power required to drive the pump, kW
beta_o=45; //Vane Angle at outlet, degrees
//Data Used:-
rho=1000; //Density of water, kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
Do=Do/1000; //m
Di=Di/1000; //m
Ds=Ds/1000; //m
Dd=Dd/1000; //m
P=P*1000; //W
//(i)Manometric Head, Hm
As=(%pi/4)*Ds^2; //m^2
Ad=(%pi/4)*Dd^2; //m^2
Vd=Q/Ad; //m/s
Vs=Q/As; //m/s
Hm=(h_d+Vd^2/(2*g))-(h_s+Vs^2/(2*g)); //m
uo=%pi*Do*N/60; // Tangential velocity of Impeller at Outlet, m/s
Vwo=uo-Vfo/tand(beta_o); //m/s
//(ii) Manometric Efficiency, eta_man
eta_man=g*Hm/(Vwo*uo)*100; //In Percentage
//(iii) The Overall Efficiency of the Pump, eta_o
eta_o=rho*Q*g*Hm/P*100; //In percentage
//Results:-
printf(" (i)Manometric Head, Hm =%.2f m \n ",Hm)
printf(" (ii) Manometric Efficiency, eta_man =%.2f Percent \n ",eta_man) //The answer vary due to round off error
printf(" (iii) The Overall Efficiency of the Pump, eta_o =%.2f Percent \n ",eta_o) //The answer vary due to round off error
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