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// Example 1.2
// Computation of (a) Current in the coil (b) Magnetic potential difference across R3
// (c) Flux in R2
//Page No. 13
clc;
clear all;
close;
// Given data
phi=0.250; // Flux in Wb
R1=10500; // First magnetic circuit parameter
R2=40000; // Second magnetic circuit parameter
R3=30000; // Third magnetic circuit parameter
N=140; // Number of turns of copper wire
// (a) Current in the coil
RParr=(R2*R3)/(R2+R3); // Parallel resistance
Rckt=R1+RParr; // Circuit resistance
I=(phi*Rckt)/N;
// (b) Magnetic potential difference across R3
F1=phi*R1; // Magnetic drop across R1
F3=(I*N)-F1; // Flux across R3
//(c) flux in R2
phi2=F3/R2;
//Display result on command window
printf("\n Current in the coil = %0.2f A ",I);
printf("\n Magnetic potential difference across R3 = %0.2f A-t ",F3);
printf("\n Flux in R2 (Wb) = %0.4f Wb ",phi2);
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