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+// Example 1.2
+// Computation of (a) Current in the coil (b) Magnetic potential difference across R3
+// (c) Flux in R2
+//Page No. 13
+
+clc;
+clear all;
+close;
+
+// Given data
+phi=0.250;               // Flux in Wb
+R1=10500;                // First magnetic circuit parameter
+R2=40000;                // Second magnetic circuit parameter
+R3=30000;                // Third magnetic circuit parameter
+N=140;                   // Number of turns of copper wire
+
+// (a) Current in the coil
+RParr=(R2*R3)/(R2+R3);      // Parallel resistance
+Rckt=R1+RParr;              // Circuit resistance
+I=(phi*Rckt)/N;
+
+// (b) Magnetic potential difference across R3
+F1=phi*R1;                  // Magnetic drop across R1
+F3=(I*N)-F1;                // Flux across R3
+
+//(c) flux in R2
+phi2=F3/R2;
+
+
+//Display result on command window
+printf("\n Current in the coil  = %0.2f A ",I);
+printf("\n Magnetic potential difference across R3 = %0.2f A-t  ",F3);
+printf("\n Flux in R2 (Wb) = %0.4f Wb ",phi2);