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// Example 9.8
// Calculation of the number of subcarriers required to transmit information.
// Page no 413
clc;
clear;
close;
//Given data
M=4;
np=2; // No of polarization
nc=24; // No of channels
bs=10*10^9; // Symbol rate per polarization
d=5000*10^3; // Transmission distance
b=22*10^-27;
ts= 49.3*10^-9;
// The total data rate
B=bs*log2(M);
T=d*b*%pi*bs;
//L=T/(b*2*%pi*N*bs);
N=(bs*ts)/2;
//Displaying results in the command window
printf("\n The number of subcarriers required to transmit information = %0.0f ",N);
// The answers vary due to round off error
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