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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Example 9.8
+// Calculation of the number of subcarriers required to transmit information.
+// Page no 413
+
+clc;
+clear;
+close;
+
+//Given data
+M=4;
+np=2; // No of polarization
+nc=24; // No of channels
+bs=10*10^9; // Symbol rate per polarization
+d=5000*10^3; // Transmission distance
+b=22*10^-27;
+ts= 49.3*10^-9;
+
+// The total data rate
+B=bs*log2(M);
+T=d*b*%pi*bs;
+//L=T/(b*2*%pi*N*bs);
+N=(bs*ts)/2;
+
+
+//Displaying results in the command window
+printf("\n The number of subcarriers required to transmit information = %0.0f ",N);
+
+// The answers vary due to round off error