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// Example 3.6
// To find a)Number of cells in given area b)Number of channels/cell c)Traffic intensity per cell d)Maximum carried traffic e)Total number of users for 2% GOS f) Number of mobiles per unique channel g)Maximum number of users could be served at one time
// Page No.84
clc;
clear;
// Given data
Area=1300; // Total coverage area in m^2
R=4; // Radius of cell in m
N=7; // Frequecy reuse factor
S=40*10^6; // Allocated spectrum in Hz
Ch=60*10^3; // Channel width in Hz
// a)Number of cells
CA=2.5981*R^2; // Area of hexagonal cell in m^2
Nc=round(Area/CA); // Number of cells
// Displaying the result in command window
printf('\n Number of cells in given system = %0.0f cells',Nc);
// b)Number of channels/cell
C1=round(S/(Ch*N)); // Number of channels
// Displaying the result in command window
printf('\n \n Number of channels per cell in given system = %0.0f channels/cell',C1);
// c) Traffic intensity per cell
C1=95; // Number of channels from b)
GOS=0.02; // Grade of service
A=84; // Traffic intensity from Erlang B chart
// Displaying the result in command window
printf('\n \n Traffic intensity in given system = %0.0f Erlangs/cell',A);
// d)Maximum carried traffic
traffic=Nc*A; // Maximum carried traffic
// Displaying the result in command window
printf('\n \n Maximum carried traffic in given system = %0.0f Erlangs',traffic);
// e)Total number of users for 2% GOS
trafficperuser=0.03; // Given traffic per user
U=traffic/trafficperuser; // Total number of users
// Displaying the result in command window
printf('\n \n Total number of users = %0.0f users',U);
// f) Number of mobiles per unique channel
C=666; // Number of channels
mobilesperchannel=round(U/C); // Number of mobiles per unique channel
// Displaying the result in command window
printf('\n \n Number of mobiles per unique channel = %0.0f mobiles/channel',mobilesperchannel);
// g)Maximum number of users could be served at one time
printf('\n \n Theoretically maximum number of served mobiles is the number of available channels in the system.')
C=C1*Nc; // Maximum number of users could be served at one time
// Displaying the result in command window
printf('\n Theoretical Maximum number of users could be served at one time = %0.0f users',C);
disp('It is 3.4% of customer base.');
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