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+// Example 3.6
+// To find a)Number of cells in given area b)Number of channels/cell c)Traffic intensity per cell d)Maximum carried traffic e)Total number of users for 2% GOS f) Number of mobiles per unique channel   g)Maximum number of users could be served at one time
+// Page No.84
+
+clc;
+clear;
+
+// Given data
+Area=1300;                          // Total coverage area in m^2
+R=4;                                // Radius of cell in m
+N=7;                                // Frequecy reuse factor
+S=40*10^6;                          // Allocated spectrum in Hz
+Ch=60*10^3;                         // Channel width in Hz
+
+// a)Number of cells
+CA=2.5981*R^2;                      // Area of hexagonal cell in m^2
+Nc=round(Area/CA);                  // Number of cells
+
+// Displaying the result in command window
+printf('\n Number of cells in given system = %0.0f cells',Nc);
+
+// b)Number of channels/cell
+C1=round(S/(Ch*N));                  // Number of channels
+
+// Displaying the result in command window
+printf('\n \n Number of channels per cell in given system = %0.0f channels/cell',C1);
+
+// c) Traffic intensity per cell
+C1=95;                               // Number of channels from b)
+GOS=0.02;                            // Grade of service
+A=84;                                // Traffic intensity from Erlang B chart
+
+// Displaying the result in command window
+printf('\n \n Traffic intensity in given system = %0.0f Erlangs/cell',A);
+
+// d)Maximum carried traffic
+traffic=Nc*A;                       // Maximum carried traffic
+
+// Displaying the result in command window
+printf('\n \n Maximum carried traffic in given system = %0.0f Erlangs',traffic);
+
+// e)Total number of users for 2% GOS 
+trafficperuser=0.03;                 // Given traffic per user
+U=traffic/trafficperuser;            // Total number of users
+
+// Displaying the result in command window
+printf('\n \n Total number of users = %0.0f users',U);
+
+// f) Number of mobiles per unique channel
+C=666;                               // Number of channels
+mobilesperchannel=round(U/C);        // Number of mobiles per unique channel
+
+// Displaying the result in command window
+printf('\n \n Number of mobiles per unique channel = %0.0f mobiles/channel',mobilesperchannel);
+
+// g)Maximum number of users could be served at one time
+printf('\n \n Theoretically maximum number of served mobiles is the number of available channels in the system.')
+C=C1*Nc;                              // Maximum number of users could be served at one time
+
+// Displaying the result in command window
+printf('\n Theoretical Maximum number of users could be served at one time = %0.0f users',C);
+disp('It is 3.4% of customer base.');