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// Example 3.4
// To find number of users for Number of channels (C) a)C=1 b)C=5 c)C=10 d)C=20 e)C=100
// Page No.80
clc;
clear;
// Given data
GOS=0.005; //G rade of Service
Au=0.1; // Traffic intensity per user
// a)To find number of users for C=1
C1=1; // Number of channels
A1=0.005; // Total traffic intensity from Erlangs B chart
U1=(A1/Au); // Number of users
U1=1; // Since one user could be supported on one channel
// b)To find number of users for C=5
C2=5; // Number of channels
A2=1.13; // Total traffic intensity from Erlangs B chart
U2=round(A2/Au); // Number of users
// c)To find number of users for C=10
C3=10; // Number of channels
A3=3.96; // Total traffic intensity from Erlangs B chart
U3=round(A3/Au); // Number of users
// Answer is varrying due to round off error
// d)To find number of users for C=20
C4=20; // Number of channels
A4=11.10; // Total traffic intensity from Erlangs B chart
U4=round(A4/Au); // Number of users
// Answer is varrying due to round off error
// e)To find number of users for C=100
C5=100; // Number of channels
A5=80.9; // Total traffic intensity from Erlangs B chart
U5=round(A5/Au); // Number of users
// Displaying the result in command window
printf('\n Total number of users for 1 channel = %0.0f',U1);
printf('\n Total number of users for 5 channel = %0.0f',U2);
printf('\n Total number of users for 10 channel = %0.0f',U3);
printf('\n Total number of users for 20 channel = %0.0f',U4);
printf('\n Total number of users for 100 channel = %0.0f',U5);
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