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+// Example 3.4
+// To find number of users for Number of channels (C) a)C=1 b)C=5 c)C=10 d)C=20 e)C=100
+// Page No.80
+
+clc;
+clear;
+
+// Given data
+GOS=0.005;             //G rade of Service
+Au=0.1;                // Traffic intensity per user
+
+// a)To find number of users for C=1
+C1=1;                  // Number of channels
+A1=0.005;              // Total traffic intensity from Erlangs B chart
+U1=(A1/Au);            // Number of users
+U1=1;                  // Since one user could be supported on one channel
+
+// b)To find number of users for C=5
+C2=5;                  // Number of channels
+A2=1.13;               // Total traffic intensity from Erlangs B chart
+U2=round(A2/Au);       // Number of users
+
+// c)To find number of users for C=10
+C3=10;                 // Number of channels
+A3=3.96;               // Total traffic intensity from Erlangs B chart
+U3=round(A3/Au);       // Number of users
+
+// Answer is varrying due to round off error
+
+// d)To find number of users for C=20
+C4=20;                 // Number of channels
+A4=11.10;              // Total traffic intensity from Erlangs B chart
+U4=round(A4/Au);       // Number of users
+
+// Answer is varrying due to round off error
+
+// e)To find number of users for C=100
+C5=100;                // Number of channels
+A5=80.9;               // Total traffic intensity from Erlangs B chart
+U5=round(A5/Au);       // Number of users
+
+// Displaying the result in command window
+printf('\n Total number of users for 1 channel = %0.0f',U1);
+printf('\n Total number of users for 5 channel = %0.0f',U2);
+printf('\n Total number of users for 10 channel = %0.0f',U3);
+printf('\n Total number of users for 20 channel = %0.0f',U4);
+printf('\n Total number of users for 100 channel = %0.0f',U5);