blob: b4b0fa65a2d3e36f1eec7ea9295d8ef5ef35952a (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
|
// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART II : TRANSMISSION AND DISTRIBUTION
// CHAPTER 10: POWER SYSTEM STABILITY
// EXAMPLE : 10.5 :
// Page number 271-272
clear ; clc ; close ; // Clear the work space and console
// Given data
V_A = 1.0 // Voltage at bus A(p.u)
Z_AB = %i*0.5 // Impedance(p.u)
S_DA = 1.0 // p.u
S_DB = 1.0 // p.u
V_B = 1.0 // Voltage at bus B(p.u)
// Calculations
// Case(i) & (ii)
X = abs(Z_AB) // Reactance(p.u)
sin_delta = 1.0*X/(V_A*V_B) // Sin δ
delta = asind(sin_delta) // δ(°)
V_2 = V_B
V_1 = V_A
Q_gB = (V_2**2/X)-(V_2*V_1*cosd(delta)/X)
// Case(iii)
V_2_3 = 1/2.0**0.5 // Solving quadratic equation from textbook
delta_3 = acosd(V_2_3) // δ(°)
// Results
disp("PART II - EXAMPLE : 10.5 : SOLUTION :-")
printf("\nCase(i) : Q_gB = %.3f", Q_gB)
printf("\nCase(ii) : Phase angle of V_B, δ = %.f° ", delta)
printf("\nCase(iii): If Q_gB is equal to zero then amount of power transmitted is, V_2 = %.3f∠%.f° ", V_2_3,delta_3)
|
