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clear;
clc;
disp('Example 5.2');
// aim : To determine
// the new volume
// Given values
P1 = 300;// original pressure,[kN/m^2]
V1 = .14;// original volume,[m^3]
P2 = 60;// new pressure after expansion,[kn/m^2]
// solution
// since temperature is constant so using boyle's law P*V=constant
V2 = V1*P1/P2;// [m^3]
mprintf('\n The new volume after expansion is = %f m^3\n',V2);
// End
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