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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2705/CH5/EX5.2/Ex5_2.sce | |
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initial commit / add all books
Diffstat (limited to '2705/CH5/EX5.2/Ex5_2.sce')
-rwxr-xr-x | 2705/CH5/EX5.2/Ex5_2.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/2705/CH5/EX5.2/Ex5_2.sce b/2705/CH5/EX5.2/Ex5_2.sce new file mode 100755 index 000000000..3e80ae408 --- /dev/null +++ b/2705/CH5/EX5.2/Ex5_2.sce @@ -0,0 +1,20 @@ +clear;
+clc;
+disp('Example 5.2');
+
+// aim : To determine
+// the new volume
+
+// Given values
+P1 = 300;// original pressure,[kN/m^2]
+V1 = .14;// original volume,[m^3]
+
+P2 = 60;// new pressure after expansion,[kn/m^2]
+
+// solution
+// since temperature is constant so using boyle's law P*V=constant
+V2 = V1*P1/P2;// [m^3]
+
+mprintf('\n The new volume after expansion is = %f m^3\n',V2);
+
+// End
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