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//Variable declaration:
Lf = 6/12 //Length of firebrick (ft)
kf = 0.61 //Thermal conductivity of firebrick (Btu/h.ft. F)
A = 480 //Surface area of wall (ft^2)
Lw = 8/12 //Length of rock wool (ft)
kw = 0.023 //Thermal conductivity of rock wool (Btu/h.ft. F)
T1 = 1900 //Temperature of insulation of firebrick ( F)
T2 = 140 //Temperature of insulation of rock wool ( F)
//Calculation:
Rf = Lf/(kf*A) //Resistance of firebrick (h. F/Btu)
Rw = Lw/(kw*A) //Resistance of rock wool (h. F/Btu)
R = Rf+Rw //Total resitance (h. F/Btu)
Q = (T1-T2)/R //Heat loss through the wall (Btu/h)
//Result:
printf("The heat loss through the wall is : %.0f Btu/h .",Q)
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