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//chapter4
//example4.2
//page68
rp=200 // ohm
Rl=800 // ohm
Edc=100 // V
// if maximum ac voltage required=Vm then
// Edc=Idc*Rl i.e. Edc=Vm*Rl/(%pi*(rp+Rl))
// thus
Vm=Edc*%pi*(rp+Rl)/Rl
efficiency=(0.406/(1+(rp/Rl)))*100
printf("required ac voltage = %.3f V \n",Vm)
printf("rectification efficiency = %.3f percentage",efficiency)
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