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+//chapter4
+//example4.2
+//page68
+
+rp=200 // ohm
+Rl=800 // ohm
+Edc=100 // V
+
+// if maximum ac voltage required=Vm then
+// Edc=Idc*Rl i.e. Edc=Vm*Rl/(%pi*(rp+Rl))
+// thus
+
+Vm=Edc*%pi*(rp+Rl)/Rl
+efficiency=(0.406/(1+(rp/Rl)))*100
+
+printf("required ac voltage = %.3f V \n",Vm)
+printf("rectification efficiency = %.3f percentage",efficiency)