blob: 8033facec68aa72b113460ab85b51b250ab40231 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
|
//scilab 5.4.1
clear;
clc;
printf("\t\t\tProblem Number 5.44\n\n\n");
// Chapter 5 : Properties Of Liquids And Gases
// Problem 5.44 (page no. 229)
// Solution
//From the saturation table at 1 psia,
hf=69.74; //Btu/lbm //saturated liquid enthalpy
hfg=1036.0; //Btu/lbm //Evap. Enthalpy
hg=1105.8; //Btu/lbm //The enthalpy of saturated steam
x=0.97; //Quality
//Because the condensation process is carried out at constant pressure,the energy equation is q=deltah.
hx=hf+(x*hfg); //the initial enthalpy //Btu/lbm
printf("The initial enthalpy is %f Btu/lbm\n",hx);
//The final enthalpy is hf=69.74.So,
deltah=hx-hf; //The enthalpy difference //Btu/lbm
printf("At 1 psia,The enthalpy difference is %f Btu/lbm\n",deltah);
printf("By the computer solution,the enthalpy difference is 1004.6 Btu/lbm");
// Saturation Properties
//--------------------------
// T=101.71 degF
// P=1.0000 psia
// z z1 zg
// v(ft^3/lbm) 0.01614 333.55
// h(Btu/lbm) 69.725 1105.4
// s(Btu/lbm*F) 0.1326 1.9774
// u(Btu/lbm) 69.722 1043.6
//Thermo Properties
//------------------------
// T= 101.71 degF
// P= 1.0000 psia
// v= 323.55 ft^3/lbm
// h= 1074.3 Btu/lbm
// s= 1.9221 Btu/lbm*F
// u= 1014.4 Btu/lbm
// x= 0.9700
//Region:Saturated
|
