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diff --git a/2417/CH5/EX5.44/Ex5_44.sce b/2417/CH5/EX5.44/Ex5_44.sce new file mode 100755 index 000000000..8033facec --- /dev/null +++ b/2417/CH5/EX5.44/Ex5_44.sce @@ -0,0 +1,41 @@ +//scilab 5.4.1
+clear;
+clc;
+printf("\t\t\tProblem Number 5.44\n\n\n");
+// Chapter 5 : Properties Of Liquids And Gases
+// Problem 5.44 (page no. 229)
+// Solution
+
+//From the saturation table at 1 psia,
+hf=69.74; //Btu/lbm //saturated liquid enthalpy
+hfg=1036.0; //Btu/lbm //Evap. Enthalpy
+hg=1105.8; //Btu/lbm //The enthalpy of saturated steam
+x=0.97; //Quality
+//Because the condensation process is carried out at constant pressure,the energy equation is q=deltah.
+hx=hf+(x*hfg); //the initial enthalpy //Btu/lbm
+printf("The initial enthalpy is %f Btu/lbm\n",hx);
+//The final enthalpy is hf=69.74.So,
+deltah=hx-hf; //The enthalpy difference //Btu/lbm
+printf("At 1 psia,The enthalpy difference is %f Btu/lbm\n",deltah);
+printf("By the computer solution,the enthalpy difference is 1004.6 Btu/lbm");
+// Saturation Properties
+//--------------------------
+// T=101.71 degF
+// P=1.0000 psia
+// z z1 zg
+// v(ft^3/lbm) 0.01614 333.55
+// h(Btu/lbm) 69.725 1105.4
+// s(Btu/lbm*F) 0.1326 1.9774
+// u(Btu/lbm) 69.722 1043.6
+
+//Thermo Properties
+//------------------------
+// T= 101.71 degF
+// P= 1.0000 psia
+// v= 323.55 ft^3/lbm
+// h= 1074.3 Btu/lbm
+// s= 1.9221 Btu/lbm*F
+// u= 1014.4 Btu/lbm
+// x= 0.9700
+
+//Region:Saturated
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